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Guessing the first two term is straight forward, but they won't work for 53. So I wanted to add another term to fix it for 53 by adding a third term. But the third term that I must add should evaluate to zero for x=5 and 8. I was able to think only floor function for that job.
Читать полностью…rem(x,4) is the reminder function. 'floor' is the largest integer less than the value of the argument.
Читать полностью…4x + rem(x,4) - 2 floor(x/10), where x=5 or 8 or 53
Читать полностью…Line AM is perpendicular to line BC
Читать полностью…but I just found out I could just use the GC for that particular mod since it’s not main focus
Читать полностью…The most general way is the Gauss-Jordan method, but it is slow
Читать полностью…in fact the textbook exercises and review exercises are suffiicient alr
Читать полностью…I feel this version of workbook is good enough. The textbooks come with workbooks
Читать полностью…Kinda...anyway thanks for sharing!
Читать полностью…You know hyperbolic functions ? I use hyperbolic substitution for the integral on LHS
Читать полностью…may I know what is your thinking process of getting this formula
Читать полностью…Hi, I need help with this puzzle. Thanks in advanced!
Find the relationship:
5 and 21
8 and 32
53 and 203
Gradient of AM X gradient of BC = -1
Because AM and BC are perpendicular to each other.
This one means, theres a line BC
Let the midpoint of BC be M
just wanna find out from anyone if there’s a one size fits all method of finding matrix inverse.
seems like there’s diff method for finding 2x2, 3x3 and so on type of matrices
alternatively, go straight to TYS, but there will be a bit of standard jump if student's foundation is not strong
Читать полностью…Hi does anyone have sec 1 NT maths paper? Thkq
Читать полностью…After further simplification u can get y as just quadratic function of x
Читать полностью…Sorry i forgotten how to do integration
Читать полностью…Hi all! Anyone able to solve? Thanks in advance!
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