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q,-4/3q, 2/3q for outer surfaces
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Читать полностью…Can anyone help with this
Читать полностью…Nah the period is coming to be 1,2,3....
Читать полностью…Period o kese pta chala
Читать полностью…Yaha shayad magnitude of slope likha gya hai
Читать полностью…Isme graph ulta banaya he na?
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Читать полностью…https://unacademy.com/course/heat-transfer-thermodynamics-msqs/RR13AGUG
We will discuss some msq problems of thermodynamics
But ans 2C aa rha hai
Читать полностью…Agar question main diatomic gas mention hai lekin yeh nahi mention hai ki it's rigid or non rigid then dof Kya lena hai?
Читать полностью…Csir ke general aptitude kis teacher ke lecture acche h...
Читать полностью…Solved it? Mera bhi problem hain iye
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Ans c
Anyone Explain this question, ans is coming out to be 2C. Is it correct
Wo trajectory wala qs solve hua?
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Читать полностью…https://unacademy.com/course/heat-transfer-thermodynamics-msqs/RR13AGUG
We will discuss some msq problems of thermodynamics
Wait I'm trying to prove this
Читать полностью…I did option b and it is because the period of this function x(t) is coming to be 0 soo a function of period 0 cannot be expanded in furier series
Читать полностью…Nahi
Adiabatic ka slope steeper hi hoga
Haa wahi to boli ans option c!
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Читать полностью…https://unacademy.com/course/30-days-crash-course-for-iit-jam/68NVDJYD
Live tomorrow at 7:00 am.. we will discuss some MCQ problems of thermodynamics
Entropy se to matlab hi nehi main to partial differential liya entropy to V ke function nehi to wo zero ho jayega
Читать полностью…Entropy constant kyun lia?
Читать полностью…This is the only way I can find but last N kam pad rha tha syad idk
Читать полностью…∆t' =0 as simultaneously in O' frame
As ∆t' =gamma(∆t-∆xv/c^2)
So.... ∆t = ∆xv/c^2...
X2-X1= ∆x
t2-t1= ∆t....
So.. ∆x/∆t = c^2/v...put v =c/2..ans c
Ho jayega easy hai ∆t'=0 rk do
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