IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 20:13

DocScanner 26-Dec-2024 12-40 am.pdf

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:30

Find no. of atoms in 1 gram of radium. 1)N=6.022*10^23/226=2.665 * 10^21 atoms.

2) decay constant=activity/N=3.7*10^10 / 2.665 *10^21 = 1.388*10^-11 per second

3)half life=ln(2)/decay constant=0.693/1.388*10^-11 =0.51* 10^11 second.

Convert this second into years. U will get near about 1600 years.

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:27

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IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:20

@Amitrnjn101 Op amp homework sir

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:18

op-amp jam pyq hw.pdf

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:10

@Amitrnjn101 sir homework

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:03

@Amitrnjn101 homework sir

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:02

@Amitrnjn101 sir op amp hw

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 18:21

esmein standing wave equation kahan se aa gya? mere a/q iska answer d hoga. option d is not a standard wave equation. In a standard wave equation, the argument of the sine function (ωt ± kx) must have units that cancel out, resulting in a dimensionless quantity (or radians).

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 17:57

Bhai, iska solution full on paper pe likh ke send karna,I know it's easy but process is confusing.


The standing wave will follow this equation

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 17:52

DocScanner 25 Dec 2024 10-18 pm.pdf

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 16:37

B = 2lambda . D/a
Inversely prop to slit width... So b nd d

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 15:07

Anyone please confirm me ki iska answer b and d dono hoga ya sirf d hoga.. .

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 14:52

https://unacademy.com/course/course-on-devices-and-electronics/2Y481P67


Live today at 7:30 pm.. we will discuss some MCQ problems of op amp...

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 14:41

Class chl rha ya nhi??

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:54

@Amitrnjn101 Sir hw

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:29

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IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:26

@Amitrnjn101 op amp HW sir

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:18

Hw sir @Amitrnjn101

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:18

@Amitrnjn101 sir op amp hw

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:07

Scanned_20241225_233507.pdf

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 19:03

5_6296361406702818495.pdf

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 18:55

@Amitrnjn101 sir op amp hw

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 17:57

The standing wave will follow this equation

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 17:55

The electric field due to the remaining charged sphere can be found by considering the electric field of the original sphere minus the electric field of the sphere that was removed. 1) Electric Field at z = -R/2 due to the Original Sphere =ρR/6ϵ0 in negative z direction. 2) Electric Field at z = -R/2 due to the Removed Sphere can be calculated by seeing that the point z = -R/2 is outside this removed sphere & using the concept for a point outside a uniformly charged sphere, the electric field is the same as if all the charge were concentrated at the center. that will be ρR/24ϵ0 in negative z direction. now subtract 2 from 1 u will get result

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 17:52

https://unacademy.com/course/30-days-crash-course-for-iit-jam/68NVDJYD


Live tomorrow at 7 am.. we will be discussing some MCQ problems of torque and angular momentum

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 15:21

b and d both. the slit width is inversely proportional to the width of the central maximum. As a result, as the slit width narrows, the centre maximum widens, and as the slit width widens, the central maximum narrows.

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 15:02

Class join ho rha hai kya??

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 14:43

I thought 7:30 ho gya🤦🏻‍♀️

IIt JAM Physics With AMIT RANJAN By Unacademy

25 Dec 2024 14:41

Opamp ki class open nhi ho rah